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58 lines
1.6 KiB
Bash
58 lines
1.6 KiB
Bash
2 years ago
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#!/usr/bin/env bash
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# vim:ts=4:sts=4:sw=4:et
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#
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# Author: Hari Sekhon
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# Date: 2022-08-18 16:53:40 +0100 (Thu, 18 Aug 2022)
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#
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# https://github.com/HariSekhon/DevOps-Bash-tools
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#
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# License: see accompanying Hari Sekhon LICENSE file
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#
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# If you're using my code you're welcome to connect with me on LinkedIn and optionally send me feedback to help steer this or other code I publish
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#
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# https://www.linkedin.com/in/HariSekhon
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#
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set -euo pipefail
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[ -n "${DEBUG:-}" ] && set -x
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srcdir="$(cd "$(dirname "${BASH_SOURCE[0]}")" && pwd)"
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# shellcheck disable=SC1090
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. "$srcdir/lib/utils.sh"
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# shellcheck disable=SC1090
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. "$srcdir/lib/kubernetes.sh"
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# shellcheck disable=SC2034,SC2154
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usage_description="
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Finds empty namespaces in the current Kubernetes cluster context and deletes them
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Kubectl must be installed and configured
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"
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# used by usage() in lib/utils.sh
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# shellcheck disable=SC2034
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usage_args=""
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help_usage "$@"
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kube_config_isolate
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timestamp "Getting list of namespaces"
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#kubectl get ns -o name |
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#sed 's|namespace/||' |
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kubectl get namespaces -o jsonpath='{range .items[*]}{.metadata.name}{"\n"}' |
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while read -r namespace; do
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if [[ "$namespace" =~ ^kube- ]]; then
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continue
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fi
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timestamp "Checking namespace '$namespace'"
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# quicker, but doesn't return all objects - should return the usual candidates though
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objects="$(kubectl get all -n "$namespace" -o name)"
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# slow but safer
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#objects="$("$srcdir/kubectl_get_all.sh" -n "$namespace" | sed 's/#.*//| /^[[:space:]]*$/d')"
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if [ -z "$objects" ]; then
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echo "$namespace"
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fi
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done
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