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62 lines
1.5 KiB
Bash
62 lines
1.5 KiB
Bash
#!/usr/bin/env bash
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# shellcheck disable=SC2230
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# vim:ts=4:sts=4:sw=4:et
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#
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# Author: Hari Sekhon
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# Date: 2019-09-27 17:54:37 +0100 (Fri, 27 Sep 2019)
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#
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# https://github.com/harisekhon/bash-tools
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#
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# License: see accompanying Hari Sekhon LICENSE file
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#
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# If you're using my code you're welcome to connect with me on LinkedIn and optionally send me feedback to help steer this or other code I publish
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#
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# https://www.linkedin.com/in/harisekhon
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#
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# Shows the path to Python libraries given as arguments
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#
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# There is a better version of this in the adjacent DevOps Python Tools repo called find_python_library_path.py
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set -euo pipefail
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[ -n "${DEBUG:-}" ] && set -x
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python="${PYTHON:-python}"
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find_python_sys_path(){
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cat <<EOF |
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from __future__ import print_function
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# more likely to be right than \$USER
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import getpass
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import os
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import sys
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user = getpass.getuser()
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for path in sys.path:
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# don't return local /Users/\$USER/Library/Python/2.7/lib/python/site-packages
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# as that is not the source of sys
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if user in path:
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continue
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if 'Python.framework' in path:
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path = path.rsplit('{}lib{}'.format(os.sep, os.sep))[0]
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print(path)
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break
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elif path.endswith('/site-packages'):
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print(path)
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break
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EOF
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"$python" #|
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#sed 's,/python/*[[:digit:].]*/site-packages,,'
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}
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if [ $# -eq 0 ]; then
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find_python_sys_path
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fi
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for arg; do
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if [ "$arg" = "sys" ]; then
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find_python_sys_path
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else
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"$python" -c "from __future__ import print_function; import $arg; print($arg.__file__)"
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fi
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done
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